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what rate will water flow out of the hole?

2006-11-07 03:07:13 · 2 answers · asked by brittenybryant 1 in Science & Mathematics Physics

2 answers

The volumetric flow rate is proportional to the pressure at the bottom (which is rho*gh, or density times gravity times fluid height) and to the area of the orifice (which is pi*r^2, where r is the radius, 1 mm = 0.001 m). There is a valve constant involved, which you can assume is equal to 1 if you're not given additional information.

2006-11-07 03:21:07 · answer #1 · answered by DavidK93 7 · 0 0

Flow out of an orifice =Cd*1/2*rho*V^2*s
Cd=coefficient of discharge
rho=density
v=velocity of flow
s=Pi.r^2 area of orifice
Flow is proportional to the water head which is
rho*g*h=density*accn.due to gravity*height

complete data is not available.

2006-11-07 04:00:45 · answer #2 · answered by openpsychy 6 · 0 0

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