My math is horrible. I think it is 14.33+ hours, but I just am not sure.
2006-11-07 02:23:49 · 10 answers · asked by front_up_evol 2 in Science & Mathematics ➔ Mathematics
Divide 833.333 by 60
833.333 ÷ 60 = 13.88888333
Multiply sixty times the decimal to obtain minutes
60x 0.88888333= 53.332998
Multiply sixty times the decimal to obtain seconds.
60 x 0.3332998 =16.66499 seconds
The answer is 13 hours 53 minutes 16 seconds
- - - - - - - - - - - -- s-
2006-11-07 02:45:11 · answer #1 · answered by SAMUEL D 7 · 1⤊ 0⤋
Divide minutes by 60 to get hours. (1 hr = 60 min)
833.333 min / (60 min/1 hr) = 13.88888333... hr (the answer)
(the 3 is the repeating part of decimal)
To expand the decimal to minutes and then to seconds.
Multiply decimal hours by 60 to get minutes
= 13 hr + .88888333... X 60 min/hr
(the 3 is the repeating part of decimal)
= 13 hr + 53.333 min
Multiply decimal minutes by 60 to get seconds
= 13 hr + 53 min + .333 X 60 sec/min
= 13 hr 53 min 19.98 sec
2006-11-07 11:53:25 · answer #2 · answered by bjs820 2 · 0⤊ 1⤋
Divide by 60.
833.333 minutes ÷ 60 hours/minute = ~13.89 hours
Actually it would be 13 hours, 53 minutes and 20 seconds.
2006-11-07 10:29:28 · answer #3 · answered by Anonymous · 0⤊ 0⤋
No is is not, you would divide the 833.333min. by 60 min. which equals an hour.so 6o into 833.333 = 13.888 with a remainder of 53 minutes. Hope this is right, but, I am quite sure. but you try it.
2006-11-07 10:37:30 · answer #4 · answered by ruth4526 7 · 0⤊ 0⤋
833.333 minutes divided by 60 min = 13.888883 hours
2006-11-07 10:32:43 · answer #5 · answered by Sweetie 3 · 0⤊ 0⤋
no it is 52 hrs approx
you divide by 60
2006-11-07 10:28:28 · answer #6 · answered by raj 7 · 0⤊ 0⤋
divide the number by 60 ...
2006-11-07 10:26:18 · answer #7 · answered by D.P 3 · 0⤊ 0⤋
13.888883 take 833.333 and divide by 60
2006-11-07 10:35:35 · answer #8 · answered by Lori 2 · 0⤊ 0⤋
just divide it in 60, then u'll get in hours
2006-11-07 11:15:42 · answer #9 · answered by hertzstudio 1 · 0⤊ 0⤋
It's 13.89 hours.
2006-11-07 10:33:38 · answer #10 · answered by Anonymous · 0⤊ 0⤋