Physics - Electrical circuit?

Question

In an electrical circuit, there is a 12v battery and two resistors in parallel. One is 14 ohms, the other is 10 ohms. What is the potential difference across the 14 ohm resistor and why? Use small words when explaining!

Thanks

Answer 1

The voltage across each resistor will be 12 volts as each is effectively directly connected to the battery.
It is the current flow through the resistors which will be different.
Volts/Ohms =Amps - that is
12/7 amps or 12/5 amps now get your calculator out!
RoyS

Answer 2

I can't help thinking there's an ambiguity in your problem statement, and the the two resistors are in series with each other and connected to (in parallel with) the battery. If so, you have a current I = E / (R1 + R2) = 12 / (10 + 14) in both resistors, and the 14 ohm resistor's voltage drop is R2 * I = 14 * 12 / (10 + 14) = 7 volts. But I could be wrong, in which case the answer is 12 volts as others have said.

Answer 3

Potential difference across 14 ohms resistor,10 ohms resistor and battery is 12 V minus total current times internal resistance of battery.
Effective resistance = 14 x 10 /(14+10)= 5.83 ohms
internal resistance of battery = r

voltage across 14 ohms resistor = 12 - r x 12 / (5.83+r)

Answer 4

The potential difference is a voltage, as you are probably aware, so ignore the answers in watts. You are describing a simple circuit in which two resistors are connected across the terminals of a battery. The potential difference across either of the resistors is just the voltage of the battery, which is 12 volts :-)

Answer 5

If the resistors are in parallel then the voltage (potential difference) across both of them is 12v (the supply voltage).

This is assuming the battery has no internal resistance.

Answer 6

3 watts

Answer 7

very simple ohms law, I = E/R = 12/2 = 6 amps. Yes, the fuse will pop.

Answer 8

watt watt watt (thats 3 watts)