find zeros of the function?

Question

12x^3 + 3x^2 -42x

Answer 1

Ha! You had an answer to that 10 min before you even asked :). Check your previous question.
By factoring x out we have
x(12x^2 + 3x -42)=0

x1=0
see reference and use equations provided
x2=14/8=7/4
x3=-16/8=-2

Answer 2

12 x^3 + 3 x^2 - 42 x factorizes into 3 x (x + 2) ( 4 x - 7), so that the zeroes are (0, -2, 7/4)

Answer 3

an excellent function whilst further to a different even function provides an excellent function. The sum of an excellent and unusual function can't be categorised as even or unusual, eg f(x) = x, is a wierd function. f(x) = x squares, is a superb function. F(x) = x + x(squared) is neither even now common. 2) The made from an excellent function and a wierd function is a wierd function. The made from 2 unusual applications is a superb function. The made from 2 even applications is a superb function.

Answer 4

3x(4x^2+x-14)
3x(4x-7)(x+2)

therefore the zeros are

0,7/4 and -2

Answer 5

3x(4x^2+x-14)=0
3x(4x^2+8x-7x-14)=0
3x(4x-7)(x+2)=0
x=0 or 7/4 or -2