orgnic cmpnd C5H8(A) form sodio derivative wich react wid C3H7I (B) to gv(C)C8H14 dis gvs n octane n reductn?

Answer 1

A is 1,3-pentadiene, also called piperylene, CH2=CHCH=CHCH3. The sodio derivative is CH2=CHCH=CHCH2- Na+. This reacts with n-propyl iodide, CH3CH2CH2-I to give 1,3-octadiene, CH2=CHCH=CHCH2CH2CH2CH3, which is reducible by H2 on a Pt catalyst to give n-octane.

A clue to A is the empirical formula, C5H8. This is of the type CnH2n-4. So A has two rings, twodouble bonds, or one ring and one double bond. The product is n-octane, with no rings, so A must have had two double bonds.