3ax + 4by - 2ay - 6bx over 2ax - 2by + ay - 4bx
Thanks!
2006-11-07 01:09:22 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
3ax+4by-2ay-6bx
=3ax-6bx-2ay+4by
=3x(a-2b)-2y(a-2b)
=(3x-2y)(a-2b)
2ax-2by+ay-4bx
=2ax-4bx+ay-2by
=2x(a-2b)+y(a-2b)
=(2x+y)(a-2b)
so 3ax+4by-2ay-6bx over2ax-2by+ay-4bx
=3ax+4by-2ay-6bx /2ax-2by+ay-4bx
=(3x-2y)(a-2b)/(2x+y)(a-2b)
= (3x-2y)/(2x+y)
2006-11-07 01:47:59 · answer #1 · answered by grandpa 4 · 0⤊ 0⤋
(3ax+4by-2ay-6bx)/(2ax-2by+ay-4bx)
=[2(2by-ay)+3x(a-2b)]/[(2x(a-2b)-(2b-ay)]
Sorry, that's the best that can be done.
You could say, let A = 2by-ay and B = a-2b
then you coud write the expression as (2A +3xB)/2xB-A)
2006-11-07 01:40:45 · answer #2 · answered by ironduke8159 7 · 0⤊ 0⤋
It's been a long time since I did these kind of problems.
2006-11-07 01:16:52 · answer #3 · answered by piojita_75 4 · 0⤊ 0⤋
1... i think
2006-11-07 01:13:33 · answer #4 · answered by Anonymous · 0⤊ 0⤋