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I really need as much help as posible on this assisgment,,,anyone one of u guys wouldnt mind helping me out,,,,zoelee24_2003@yahoo.com

2006-11-07 00:05:27 · 8 answers · asked by zoelee24_2003 1 in Science & Mathematics Physics

8 answers

Equation for final velocity at the given instant is v = u + at
Whence, v,u,a,t are velocity, initial velocity, acceleration and time respectively.
Substituting the values we have, v= 5 + 1.5*9 = 18.5m/s

2006-11-07 00:28:58 · answer #1 · answered by shasti 3 · 0 0

Howdy & I surely hope you're doing well. :) Well I'm not an authority on physics & I hope I understand this correctly. :) From the example cited at MSN Encarta Encyclopaedia, if I understand it right, you're supposed to multiply the time elapsed by the acceleration, then add it to the original velocity of the car. Meaning:

1.5 m/s2 x 9s = 13.5 m/s
13.5 m/s + 5 m/s = 18.5 m/s

Like I said, I'm not an authority on physics & wouldn't stake my honour or reputation on the answer, as it may well be wrong. But, to my mind, the explanation & example given on the page I listed in my sources seems to indicate the operation displayed above. I sure hope this helps. :) Good luck on your assignment. :) Take very good care & have a great day. :)

2006-11-07 08:21:14 · answer #2 · answered by Cogano 3 · 0 0

Acceleration is the CHANGE in speed over time.
Since the car accelerates at 1.5 m/s^2 the speed has chaged by 9s * (1.5 m/s^2) which equals 13.5 m/s.
Note that in that step, I kept the unit (s) associated with the time factor. When that unit is multiplied, it cancels one of the square seconds and your answer is in meters per second.
Since that is the change in speed, you have to add the original speed to get the current speed.
13.5 m/s + 5 m/s = 18.5 m/s

2006-11-07 08:28:40 · answer #3 · answered by Trailcook 4 · 0 0

Just remember the formula for that:
vf = vi + at
vf = 5 m/s + (1.5 m/s^2)9
vf = 5 m/s + 13.5 m/s^2
vf = 18.5 m/s

Hope it helps..... thanX!

2006-11-07 08:27:24 · answer #4 · answered by Ryan 3 · 0 0

u=5m/sec, a=1.5m/sec^2,t=9sec
we have the kinematic equation
v=u+at
=5+1.5*9
=5+13.5
=18.5m/sec

2006-11-07 08:12:22 · answer #5 · answered by openpsychy 6 · 1 0

Fast

2006-11-07 08:10:33 · answer #6 · answered by SilverSurfer 4 · 0 2

41mph (66kmph) - not that fast! unless it's a built-up area, careful....!!**FLASH**!! speed camera, ching ching...it was a 30 limit get yer credit card out!

??who gave me a bad rating for that?? 18.5m/s = 66kmph c'mon guys play the game....

2006-11-07 08:17:46 · answer #7 · answered by ? 7 · 0 2

18.5

2006-11-07 08:08:40 · answer #8 · answered by zolleymokus 1 · 0 0

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