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Okay...I'm really confused, and need some help...

The problem is x-6<7

(The "<" sign has a line under it!!!!!!)

2006-11-06 17:26:02 · 7 answers · asked by Anonymous in Science & Mathematics Mathematics

Umm...yeah I really don't know what a regular equality thing is...

2006-11-06 17:28:52 · update #1

7 answers

Solve it just like a regular equality:

x-6 ≤ 7

Add 6 to both sides, to get:

x ≤ 13 ← this is your answer

When working with inequalities, you can add and subtract from both sides just as you would in a regular equality. You can also multiply and divide both sides, but the trick to keep in mind is that if you multiply or divide by a negative number, you need to change the sign! For example, if you had:

-2x ≤ 10

Divide both sides by -2 AND REVERSE THE INEQUALITY to get:

x ≥ -5

Hope that helped!

~ ♥ ~

EDITED TO ADD: A "regular equality" would be where you have an equal sign rather than a < or > sign. So x-6 = 7 is an equality.

Good luck kid ... sounds like you will need it!

2006-11-06 17:27:52 · answer #1 · answered by I ♥ AUG 6 · 1 0

The line under the < sign means less than or equal. Solve it like a regular equation.

2006-11-06 17:31:17 · answer #2 · answered by Michael T 1 · 0 0

i'm no longer an authority in this, yet I performed with it for exciting. a^b + b^a > a million ln(a^b + b^a) > ln(a million) ln(a^b) + ln(b^a) > 0 b*ln(a) + a*ln(b) > 0 b*ln(b) > -a*ln(a) (expr a million): b*ln(b)/a*ln(a) > -a million be conscious that: ln(x) = 0 for x = a million ln(x) > 0 for x > a million ln(x) < 0 for x >= 0 < a million ln(x) techniques -infinity while x techniques 0 ln(x) is imaginary for x < 0 So if a and b are > a million then expr a million is genuine And if a and b are > 0 < a million then expr a million is genuine. And if a and b = 0 then expr a million is genuine. And if a and b = a million then expr a million is genuine And if b = a million and a > 0 expr a million is genuine And if a or b < 0 then expr a million is fake if b > a million and a >=0 < a million it gets complicated: if b*ln(b) >= a million and -a million < a*ln(a) < 0 then expr a million would be fake If b >= a million.763 and a < a million then expr a million is fake So: if b > a million.763 and a > a million then expr a million is genuine it form of feels as though there are limitless opportunities and greater than a number of different distinctive stages of values which will artwork. i assume i'm unsure what "belonging to (0,a million)" ability precisely. replace: If a and b are > 0 < a million then expr a million is genuine because of the fact the LHS of expr a million will continually be constructive and for this reason greater suitable than RHS of expr a million (-a million).

2016-10-15 11:32:44 · answer #3 · answered by ? 4 · 0 0

x-6 =< 7

This means the expression x-6 is less than or equal to 7.
The problem being to find a real range of x such that this inequality holds.
Manipulation doesn't vary much from handling standard equalities,
i.e.
add 6 to both sides gives,
x =< 13
and that's the answer!

2006-11-06 18:35:01 · answer #4 · answered by yasiru89 6 · 0 0

so x - 6 is less than or equal to 7.

Add 6 to both sides of the equation.

x is less than or equal to 13

2006-11-06 17:32:32 · answer #5 · answered by vabanu 2 · 0 0

x-6<=7
add 6 to both sides
x<=13
it means less than or equal to

2006-11-06 17:28:14 · answer #6 · answered by raj 7 · 0 0

then x<13.. with the line under the < symbol..

2006-11-06 17:38:27 · answer #7 · answered by lologonol 1 · 0 0

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