Explain
2006-11-06 16:26:25 · 9 answers · asked by boyz_inblu3 1 in Science & Mathematics ➔ Mathematics
Multiply 3 on both sides to get rid of the fractions
3(5d-2/3)=3(1/3d)
15d-2=d
Subtract 15d on both sides:
-14d=-2
Divide -14 on both sides:
d=2/14=1/7
Check:
5(1/7)-2/3=1/3(1/7)
5/7-2/3=1/21
15/21-14/21=1/21
1/21=1/21
2006-11-07 02:00:26 · answer #1 · answered by Anonymous · 4⤊ 0⤋
5d - 1/3d = 2/3
(15/3)d - 1/3d = 2/3
(14/3)d = 2/3
14d = 2
d = 2/14 = 1/7
2006-11-06 16:49:35 · answer #2 · answered by J.J. 2 · 1⤊ 0⤋
5d-2/3=1/3d
Multiply equation by 3.
15d-2=d
15d-d=2
14d=2
d=1/7
Put it back in the equation to check.
2006-11-06 16:42:52 · answer #3 · answered by Michael T 1 · 1⤊ 0⤋
Is it (a million+5d)/10 or a million+(5d/10)? that is both p=(a million+5d)/10 10p=a million+5d 10p-a million=5d (10p-a million)/5=d 2p-(a million/5)=d Or that is p=a million+(5d/10) p-a million=5d/10 10(p-a million)=5d 10p-10=5d (10p-10)/5=d 2p-2=d in case you in basic terms have 2 variables on your equation and no squared, cubed, rooted and so on. words, you in basic terms placed it into the type y=mx+c and draw a graph of that. operating example d=2p-2 y=mx+c The y axis is d, the x axis is p. you've a instantly line graph of gradient 2, shifted 2 down on the y axis.
2016-11-28 21:02:10 · answer #4 · answered by ? 4 · 0⤊ 0⤋
5d-1/3d=2/3
14/3d=2/3
14d=2
d=1/7
2006-11-06 16:28:41 · answer #5 · answered by vagarant 2 · 1⤊ 0⤋
.5d=1/2d
Therefore, .5d-2/3=1/3d is the same as 1/2d-2/3=1/3d
1/2d-1/3d=2/3
d(1/2-1/3)=2/3
d(3/6-2/6)=2/3
d(1/6)=2/3
d=2/3*6=4
2006-11-06 16:30:29 · answer #6 · answered by bruinfan 7 · 0⤊ 2⤋
5d- 2/3=1/3d
5d-(1/3)d=2/3
(14/3)d=2/3
7d=1
d=1/7=.142857
2006-11-06 16:59:03 · answer #7 · answered by yupchagee 7 · 1⤊ 0⤋
2/17
2006-11-06 16:30:44 · answer #8 · answered by avinashseepaul 1 · 0⤊ 2⤋
5d-2/3=1/3d
14/3d=1/3d
------ -----
14/3 14/3
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1d=1/7
2006-11-06 16:39:36 · answer #9 · answered by ptaylor340 1 · 1⤊ 0⤋