partscoretotalsubmissions1--10/10A car (mass = 1130 kg) is traveling at 35 m/s when it collides head-on with a sport utility vehicle (mass = 2210 kg) traveling in the opposite direction. In the collision, the two vehicles come to a halt. At what speed was the sport utility vehicle traveling?
2006-11-06 16:19:33 · 5 answers · asked by Alan l 1 in Science & Mathematics ➔ Physics
This is a momentum question. If the end result is comming to a halt, then then each vehicles' momentum was equal and opposite. Momentun (M) = mass (m) * velocity (v), therefore you are left needing to solve the equation m1*v1 = m2*v2...you can do the rest I hope....
2006-11-06 16:25:08 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Let the speed of sport utility vehicle = x m/s
Momentum before the collision and after the collision remains the same. Therefore
1130*35 + 2210*x = (1130+2210) * 0
x = - (1130*35/2210)
x = - 17.90 m/s (-ve means from opposite direction).
Best regards
Sameer
2006-11-07 00:34:53 · answer #2 · answered by sameer_nigam 1 · 0⤊ 0⤋
Conservation of momentum: Momentum before collision is 1130*35-2210*v2. Momentum after collision is 0 (nothing is moving). Therefore 1130*35-2210*v2=0. Solve for v2
2006-11-07 00:26:03 · answer #3 · answered by gp4rts 7 · 0⤊ 0⤋
1130 x 35 = 2210 x ?
Inertia = mass x speed. The inertia would be equal (and in the question it assumes no friction...)
Do the math.
2006-11-07 00:22:19 · answer #4 · answered by Anonymous · 0⤊ 0⤋
17.9 m/s
2006-11-07 02:02:03 · answer #5 · answered by Da Funk 5 · 0⤊ 0⤋