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Write the log as a single quantity.

1/2 [4 log (x - 2) + log (x + 3 ) - log 5]

2006-11-06 16:14:21 · 2 answers · asked by Laura 3 in Science & Mathematics Mathematics

2 answers

First 4*log[x-2] = log[x-2]^4.
Then -log[5] = log[1/5]

The sum of logs is the log of the product of the arguments and so this gives

(1/2)*log[(x-2)^4 * (x+3) / 5]

Finally the (1/2) becomes an exponent in the argument:

log[((x-2)^4 * (x+3) / 5)^(1/2)]

2006-11-06 16:21:23 · answer #1 · answered by gp4rts 7 · 0 0

=1/2[log(x-2)^4+log(x+3)-log5]
=1/2[log((x-2)^4x(x+3))/5]
=log[((x-2)^4.(x+3)/5)^(1/2)]

2006-11-07 00:17:59 · answer #2 · answered by Anonymous · 0 0

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