The 5 is throwing me off.
2006-11-06 16:13:03 · 6 answers · asked by Lou-Lou 2 in Science & Mathematics ➔ Mathematics
It has one real solution. Irrational roots are always in groups of two, so there could have been one or three real solutions.
The real solution is -0.531447857. Unfortunately, there is not any easy way to find this one other than guess and check.
You will also note that plotting the line x^3-4x^2+7x+5=y is always increasing. (The first derivative is always positive). This tells you that you are guaranteed to only have one real solution.
And 2.26... doesn't work
2006-11-06 16:24:10 · answer #1 · answered by c 3 · 1⤊ 0⤋
By the rational root theorem, this equation could only have plus or minus 1 or plus or minus 5 as rational solutions; and since none of these numbers work, this equation has no rational solutions. Therefore, the only solutions will be irrational: in this case there will only be 1 solution--approximately -2/3.
2006-11-06 16:19:14 · answer #2 · answered by bruinfan 7 · 0⤊ 0⤋
You need to do turn off the pc and do your own homework, you will thank me one day for telling you this.
2006-11-06 16:20:40 · answer #3 · answered by Chad 7 · 0⤊ 0⤋
X= -0.531449282 , 2.265724642
The other answer is repeated.
2006-11-06 16:23:40 · answer #4 · answered by A 150 Days Of Flood 4 · 0⤊ 1⤋
ow... my head hurts just looking at it... sorry......
2006-11-06 16:14:24 · answer #5 · answered by Stan 5 · 0⤊ 0⤋
You didn't say 'please.'
2006-11-06 16:15:55 · answer #6 · answered by Emm 6 · 0⤊ 0⤋