3x(x-4)-1(x-4)
3x^2-12x-x+4
3x^2-13x+4
2006-11-06 16:12:27
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answer #1
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answered by raj 7
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Use the FOIL method (First, Outer, Inner, Last) and multiply the terms within the parenthesis.
You should end up with: 3x^2-13x+4
2006-11-06 16:02:58
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answer #2
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answered by Anonymous
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3x times x plus -1 times x plus 3x times -4 plus -1 times -4
2006-11-06 16:01:56
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answer #3
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answered by crage_ralius 3
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Remember FOIL
First, Outer, Inner, Last
3x^2 - 12x -x + 4
3x^2 - 13x + 4
2006-11-06 16:04:09
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answer #4
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answered by Dianna S 2
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3x^2 -x -12x + 4 = 3x^2 -13x + 4
2006-11-06 16:03:18
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answer #5
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answered by Dr. J. 6
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Use FOIL first outer inner last
3x^2 - 12x - x + 4
3x^2 -13x +4
2006-11-06 16:03:09
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answer #6
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answered by bourqueno77 4
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3x^2 - 13x + 4
(^2 means squared)
2006-11-06 16:03:22
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answer #7
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answered by Anonymous
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(3x-1)(x-4) times them together
3x^2-12x-x+4 add 'em up
3x^2-13x+4
hopefully that's right.
2006-11-06 16:04:44
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answer #8
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answered by pacific_crush 3
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FOIL: 3x2-12x-x+4
3x2-13x+4
2006-11-06 16:01:56
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answer #9
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answered by blue_bee 4
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Hello.......this is the simplified expression......there is no way to simplify it anymore
If you want it to be expanded...the answer would be 3X^2-13X+4
2006-11-06 16:06:46
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answer #10
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answered by Anonymous
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