y= x^2+7x+12?

Question

write the quadratic function in intercept form and give the functions zeros.

Answer 1

I dont think there is such a thing as intercept form for quadratics. The zeroes are -3 and -4.

If you put it in vertex form, it would be Y + 0.25 = (x + 3.5)^2
That would make the vertex (-3.5, -0.25).

Answer 2

somewhat, an intercept potential the fee of one variable whilst the different variable is 0. because x is a function of the 2nd degree (y = x^2 + 7x + 12), element y = (x + 4)(x+ 3) the y intercept is the fee whilst x is 0 substituting for y intercept y = (0 + 4)(0 + 3) y = (4)(3) y = 12 the x intercept, on the different hand is the fee of x whilst y is 0 substituting for x intercept 0 = (x + 4)(x + 3) because there are 2 x's, we merely chop up the equation into 2 (presented that each and each x has a potential of one, consequently factorization) (x + 4) = 0 and (x + 3) = 0 fixing for values of x we get: x = -4 and x = -3

Answer 3

Here is the factor: You can use this to plot X,Y intercepts

y=(x+3)(x+4)