Ok so this problem is driving me crazy.
If you add 2.22 g of sodium azide (NaN3 an ionic salt) to the solution of 0.734 g NH3(hydrogen azide) in 400 mL of water.
what will the new pH be? (Assume no volume change).
Please show work, so I can figure this out :) thanks!!
2006-11-06 14:44:24 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
Flaw in problem statement: hydrogen azide is HN3 -- NH3 is ammonia. As usual, you will need the molar concentrations. if the salts fully dissociate, the hydrogen from the HN3 will be added to the hydrogen in the water, and you can add these up to get the total hydrogen present. From that, you can get the pH.
2006-11-06 14:59:45 · answer #1 · answered by Anonymous · 0⤊ 0⤋
alll you need is sodiume coloride and alittle chemstry set and you will have a glow stick
i think they cancel each other out but i am tired
2006-11-06 22:59:49 · answer #2 · answered by Talking Hat 6 · 0⤊ 0⤋
i can't help you but i want 10 points thanks :)
2006-11-06 22:46:27 · answer #3 · answered by bob l eponge 5 · 0⤊ 0⤋