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2006-11-06 14:38:50 · 5 answers · asked by jeflvscrs 1 in Science & Mathematics ➔ Mathematics
x-5y=2.......Eq 1
7y-3x=10.......Eq 2
Consider Eq 1
x - 5y = 2
x = 2 + 5y
Substitute the derived value of 'x' in Eq 2
7y-3x=10
7y - 3(2 + 5y) = 10
7y - 6 - 15y = 10
-8y = 10 + 6
-8y = 16
y = 16/-8
y = -2
Substitute the value of 'y' in Eq 1
x-5y=2
x - 5(-2) = 2
x + 10 = 2
x = 2-10
x = -8
The ordered pair is : (-8,-2)
2006-11-07 00:03:54 · answer #1 · answered by Akilesh - Internet Undertaker 7 · 0⤊ 0⤋
One the first equation x = 2+5y now sub that in to prob #2 to get 7y-3(2+5y)=10 7y-6-15y=10 -8y=16 y=-2 now plug this in to the first equation. So x = 2 - 5(-2) in which x = 12 So your intersect coordinates (ordered pair) are (12,-2)
2006-11-06 14:50:11 · answer #2 · answered by bourqueno77 4 · 0⤊ 0⤋
so first get the x byitself in the first equation
so its x=5y+2
then subsitute 5y+2 for x in the second equation
7y+3(5y+2)=10
7y+15y+6=10
22y+6=10
22y=4
y=4/22=2/11
2006-11-06 14:46:50 · answer #3 · answered by googleslaps 2 · 0⤊ 0⤋
From First equation x=2+5y
substituete it in seconed one:
7y-3(2+5y) = 10
Solve it for y & then get x from substituting its value in first equation
2006-11-06 14:49:29 · answer #4 · answered by Anonymous · 0⤊ 0⤋
x-5y=2 this is equation 1
7y-3x=10 this is equation 2
use equation 1 to solve this quetion so
x=2+5y this is equation 3
subtitue 3 into 2
7y-3(2+5y)=10
7y-6-15y=10
-8y-6=10
-8y=16
y=16/-8
y=-2
subtitue y=-2 into equation 1
x-5(-2)=2
x+10=2
x=2-10
x=-8
so the answer is x=-8 and y=-2
2006-11-06 15:16:36 · answer #5 · answered by Chong Sian C 3 · 0⤊ 0⤋