(a) How many seconds was the rock in the air?
(b) How far out from the base of the cliff does the rock land?
2006-11-06 14:17:54 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Physics
please show steps
2006-11-06 14:25:53 · update #1
d = 1/2 a * t^2
98m =(1/2) * 9.8m/s/s * t^2
20 sec^2 = t^2
t = 4.47 sec
d = v * t
d = 27m/s * 3.16sec
d = 120.7 m
2006-11-06 14:23:49 · answer #1 · answered by juan70ahr 3 · 0⤊ 0⤋
From d = a million/2 g t^2, resolve for t^2 = 2nd/g = 294/9.8 = 30, so t = 5.40 8 seconds to fall to the floor even with any horizontal velocity. If it is going 80m horizontally in 5.40 8 seconds, that velocity is 80/5.40 8 = 14.6 m/s.
2016-10-15 11:26:02 · answer #2 · answered by ? 4 · 0⤊ 0⤋
People in glass houses should not throw rocks.
2006-11-06 14:20:48 · answer #3 · answered by Donna L 3 · 0⤊ 1⤋
HEy! Watch wear you throw that!
2006-11-06 14:20:23 · answer #4 · answered by Anonymous · 0⤊ 1⤋
a) 4.472 sec
b) 120.75 m
i'm sure these are rite, i'm in second yr physics at my high school
2006-11-06 14:23:15 · answer #5 · answered by YOYO 2 · 0⤊ 0⤋
How long does it take to fall?
2006-11-06 14:20:06 · answer #6 · answered by arbiter007 6 · 0⤊ 0⤋
but what if a boy throws it?
2006-11-06 14:20:09 · answer #7 · answered by goodtimesgladly 5 · 0⤊ 1⤋