English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

I will love u 4 ever

2006-11-06 13:49:21 · 9 answers · asked by jeflvscrs 1 in Science & Mathematics Mathematics

9 answers

First solve for y.
3x - 5y = 7
Subtract 3x from each side
-5y = -3x + 7
Divide everything by -5
y = (3/5)x - 7/5
The slope is m = 3/5
SInce the new line is parallel to the given line, that means the slope will be the same. Use your given point to find the line
y - (-7) = (3/5)(x-6)
y + 7 = (3/5)x - 18/5
y = (3/5)x - 18/5 - 7
y = (3/5)x - 53/5

2006-11-06 13:53:39 · answer #1 · answered by MsMath 7 · 2 3

line parallel to ax+by+c =0

is of the form ax+by+k =0 where k is to be found out using the given conditions

therfore required line is of the form 3x-5y = k . Since this passes through (6,-7) we get 18 +35 = k or k = 53

so equation is 3x-5y =53

or y = (3/5)x + (53/5)

2006-11-06 22:52:19 · answer #2 · answered by qwert 5 · 0 1

First put the line into y = mx + b form:
3x - 5y = 7
-5y = -3x + 7
y = (3/5)x - 7/5

So your slope is 3/5. The parallel line will also have a slope of
3/5.

You have a point (6,-7) and a slope 3/5. Now to figure the equation for the new line:
y = mx + b
y = (3/5)x + b

Plug in the point (x = 6, y = -7):
(-7) = 3/5(6) + b

Solve for b:
-7 = 18/5 + b
b = -7 - 18/15
b = (-35 - 18)/5
b = -53/5

So the equation for your parallel line through (6, -7) is:
y = (3/5)x - 53/5

Equivalently you can use point slope form for the line:
(y - y1) = m(x - x1)
y - (-7) = (3/5)(x - 6)
y + 7 = 3/5(x - 6)

Notice how this transforms to slope-intercept form:
y = 3/5x - 18/5 - 7
y = 3/5x - 53/5

2006-11-06 21:53:39 · answer #3 · answered by Puzzling 7 · 2 3

3x - 5y = 7

Parallel line of form 3x - 5y = k
Line passes through (6, -7) so when x = 6 y = -7
Therefore 3x - 5y = 3 x 6 - 5 x -7 = 53
So the required line is 3x - 5y = 53
(ie 5y = 3x - 53 So y = 3/5 x - 53/5)

By the way all perpendicular lines are of the form 5x + 3y = k

2006-11-06 22:04:01 · answer #4 · answered by Wal C 6 · 0 1

First change your equation around.
3x-5y=7
-5y=-3x+7
y=3/5x+ 7/5

Now plug in your points.
(X,Y)
(6,-7)

-7=(3/5)6+?
?=-10.6

That is your y-intercept.

y=3/5x-10.6

It is parallel because the slope is the same.

2006-11-06 22:00:38 · answer #5 · answered by Anonymous · 0 1

Eq of this line paralle to this is 3x-5y=k;
since it passes thru (6,-7) k=53
3x-5y=53

y=(3x-53)/5

2006-11-07 12:13:40 · answer #6 · answered by Anonymous · 0 1

The equation is y = 3/5x - 53/5

2006-11-06 21:53:45 · answer #7 · answered by Evan L 2 · 0 2

slope of 3x-5y=7 is 3/5,
so
y+7=3/5(x -6)
!

2006-11-06 21:52:12 · answer #8 · answered by locuaz 7 · 1 2

So, you should figure out the SLOPE of the line in the equation, because any line parallel to it will have the SAME SLOPE.

Hint:

Y=?x+?

Then use the point-slope formula to figure out the equation of the new line!

2006-11-06 21:52:53 · answer #9 · answered by Anonymous · 0 1

fedest.com, questions and answers