First solve for y.
3x - 5y = 7
Subtract 3x from each side
-5y = -3x + 7
Divide everything by -5
y = (3/5)x - 7/5
The slope is m = 3/5
SInce the new line is parallel to the given line, that means the slope will be the same. Use your given point to find the line
y - (-7) = (3/5)(x-6)
y + 7 = (3/5)x - 18/5
y = (3/5)x - 18/5 - 7
y = (3/5)x - 53/5
2006-11-06 13:53:39
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answer #1
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answered by MsMath 7
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line parallel to ax+by+c =0
is of the form ax+by+k =0 where k is to be found out using the given conditions
therfore required line is of the form 3x-5y = k . Since this passes through (6,-7) we get 18 +35 = k or k = 53
so equation is 3x-5y =53
or y = (3/5)x + (53/5)
2006-11-06 22:52:19
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answer #2
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answered by qwert 5
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First put the line into y = mx + b form:
3x - 5y = 7
-5y = -3x + 7
y = (3/5)x - 7/5
So your slope is 3/5. The parallel line will also have a slope of
3/5.
You have a point (6,-7) and a slope 3/5. Now to figure the equation for the new line:
y = mx + b
y = (3/5)x + b
Plug in the point (x = 6, y = -7):
(-7) = 3/5(6) + b
Solve for b:
-7 = 18/5 + b
b = -7 - 18/15
b = (-35 - 18)/5
b = -53/5
So the equation for your parallel line through (6, -7) is:
y = (3/5)x - 53/5
Equivalently you can use point slope form for the line:
(y - y1) = m(x - x1)
y - (-7) = (3/5)(x - 6)
y + 7 = 3/5(x - 6)
Notice how this transforms to slope-intercept form:
y = 3/5x - 18/5 - 7
y = 3/5x - 53/5
2006-11-06 21:53:39
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answer #3
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answered by Puzzling 7
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3x - 5y = 7
Parallel line of form 3x - 5y = k
Line passes through (6, -7) so when x = 6 y = -7
Therefore 3x - 5y = 3 x 6 - 5 x -7 = 53
So the required line is 3x - 5y = 53
(ie 5y = 3x - 53 So y = 3/5 x - 53/5)
By the way all perpendicular lines are of the form 5x + 3y = k
2006-11-06 22:04:01
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answer #4
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answered by Wal C 6
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First change your equation around.
3x-5y=7
-5y=-3x+7
y=3/5x+ 7/5
Now plug in your points.
(X,Y)
(6,-7)
-7=(3/5)6+?
?=-10.6
That is your y-intercept.
y=3/5x-10.6
It is parallel because the slope is the same.
2006-11-06 22:00:38
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answer #5
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answered by Anonymous
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Eq of this line paralle to this is 3x-5y=k;
since it passes thru (6,-7) k=53
3x-5y=53
y=(3x-53)/5
2006-11-07 12:13:40
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answer #6
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answered by Anonymous
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The equation is y = 3/5x - 53/5
2006-11-06 21:53:45
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answer #7
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answered by Evan L 2
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slope of 3x-5y=7 is 3/5,
so
y+7=3/5(x -6)
!
2006-11-06 21:52:12
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answer #8
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answered by locuaz 7
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So, you should figure out the SLOPE of the line in the equation, because any line parallel to it will have the SAME SLOPE.
Hint:
Y=?x+?
Then use the point-slope formula to figure out the equation of the new line!
2006-11-06 21:52:53
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answer #9
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answered by Anonymous
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