how do a write a parallel line in slope intercept form?

Answer 1

The important thing is that parallel lines have the same slope, so the slope will be the same as the line you are given. Most likely that line is also in slope/intercept form (y=mx+b), so the slope would be the number by "x".

If they give you a y-intercept, that's the "b" in y=mx+b. You just plug in "m" and "b", and you're done.

If they instead give you another point, you'd most likely use the point/slope formula y-y1=m(x-x1). You plug the numbers you're given for the point in for "x1" and "y1" and the slope for "m". You'd then multiply out the parentheses and move the y1 over to the other side so your final answer is in the form y=mx+b.

Answer 2

A line is given by the form y=mx+b,

where:
m is the slope of the line and b is the y intercept of that line (or where it crosses the y axis. Parallel lines always have the same slope, so the only thing to find is the y-intercept.

For example, if you have this:

find the slope of a line parallel to y=2x+3 that passes through the point 0, 4,

You know the slope will be 2 and the line will pass through the int at y=3. Remember. To find the y-intercept, just set x equal to 0.

Answer 3

slope intercept form is y =mx + b
so to write an equation for a parallel line simply use the same slope (m)

Answer 4

find where the points meet and then make that as a cordanet plane and that sood do it