2/x-1+3/x+2=2?

Question

find x

Answer 1

Multiply each side by (x-1) and (x+2)

2(x+2) + 3(x-1) = 2 (x-1)(x+2)
2x+4 + 3x -3 = 2x^2 +2x -4
0= 2x^2 -3x -5
0=(2x-5)(x+1)
so x = 5/2 or x = -1

Answer 2

Most of these answers are false. it cannot equal 5 because if u plug it in would give u an answer of .9285. what u do is multiply all of the equation by (x-1)(x+2) which gives u

2x+4+3x-3=2x²+2x-4

you then combine the terms and get

2x²-3x-5=0

you factor and get

(2x-5)(x+1)=0

then u set them both equal to 0

2x-5=0 and x+1=0

and get

x=5/2,-1 as answers

Answer 3

5=x

Answer 4

Multiply both sides by the common demoninator:
2(x-1)(x+2)/(x-1) + 3(x-1)(x+2)/(x+2) = 2(x-1)(x+2)

Simplify:
2(x+2) + 3(x-1) = 2(x^2+x-2)

Distribute
2x+4+3x-3 = 2x^2+2x-4

Simplify again
5x+7 = 2x^2+2x-4
2x^2-3x-11 = 0

then factor to find x (its not factorable, so you'll need to use quadratic formula)

Answer 5

Command
Solve, showing approximate solutions to 6 digits.


Equation

1+ 5/x = 2



Varible

x


Result

Exact

Solution 1 (real)

x = 5




Approximate

Solution 1 (real)

X = 5.

Answer 6

2/x-1+3/x+2=2

5/x+1=2

5/x=1

x=5

Answer 7

x≠-2 or 1

Multiply both sides by (x+2)(x-1):
2(x+2)+3(x-1)=2((x-1)(x+2))

Distributive property:
2x+4+3x-3=2x^2+2x-4

Combine like terms:
5x+1=2x^2+2x-4

Subtract 5x and 1 to both sides:
2x^2-3x-5=0

Factoring:
(2x-5)(x+1)=0
x=-1 and 5/2

Check:
2(5/2)-5=0
5-5=0
0=0

-1+1=0
0=0

I hope this helps!

Answer 8

2/x-1+3/x+2=2
add 1 and subtract 2 from each side

2/x+3/x=1
2/x+3/x=5/x
5/x=1

x=5

Answer 9

5
-2
+1
*x
2+3
5=x

Answer 10

You have to get a common denominater for those two fractions.
so multiply the first one by (x+2)/(x+2) and the second by (x-1)/(x-1) and you should be able to algebretically get the rest:)