Three times a number, increased by 32, has the same value as four times the number, decreased by 15. Find the number.
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I tryed finding the number, but it didn't fit the choices. Help would be apperciated.
2006-11-06 11:03:07 · 6 answers · asked by Oh dear 2 in Science & Mathematics ➔ Mathematics
Put that in equation, it is algebra time.
(3 * x) + 32 = (4 * x) - 15
Now we resolve... add 15 both sides (and -15 + 15 is of cource zero, as they cancel each other) and substract 3x both sides as well, so you have
32 + 15 = 4x - 3x
47 = x
That is your number: 47
2006-11-06 11:06:49 · answer #1 · answered by Vincent G 7 · 0⤊ 0⤋
3x + 32= 4x -15
-3x = -3x
32= 1x -15
+15 +15
47= 1x
1= 1
47 = x
So as worked in the problem x should equal 47
2006-11-06 11:11:45 · answer #2 · answered by ddm0211 2 · 0⤊ 0⤋
you cant solve by guessing. we dont know the number, so lets call it 'x'
3 times a number increased by 32 = 3x+32
4 times a number decreased by 15 = 4x-15
set the two equal to each other
3x+32=4x-15
subtract 32 from both sides and you get; (you want to get 'x' by itself)
3x=4x-47
subtract 4x from both sides and you get
-1x = -47
divide both sides by -1 and get
x=47
to check , replace x in the original equation with 47
3x+32=4x-15
3(47)+32 = 4(47)-15
141+32 = 188-15
173 = 173
2006-11-06 11:10:43 · answer #3 · answered by tma 6 · 0⤊ 0⤋
Let the number be 'x'
3x + 32 = 4x - 15
3x = 4x - 15 - 32
3x = 4x - 47
3x - 4x = -47
-x = -47
x = 47
The number is 47
2006-11-06 11:57:19 · answer #4 · answered by Akilesh - Internet Undertaker 7 · 0⤊ 0⤋
47
2006-11-06 11:08:15 · answer #5 · answered by Anonymous · 0⤊ 0⤋
3x+32=4x-15
3x+32-15=4x
47=4x-3x
47=x
2006-11-06 11:14:02 · answer #6 · answered by msX 6 · 0⤊ 0⤋