algebra
radical y+1= radical (y+6) -1
the minus 1 isnt part of the radical its used after the y+6
please help i cant figure it out
2006-11-06 11:00:33 · 7 answers · asked by sarah anne 1 in Science & Mathematics ➔ Mathematics
so (radical y+1) squared = (radical (y+6) +1)squared
y+1 = y+6 - 2(radical y+6) +1
y+1 = y+7 - 2(radical y+6)
1 = 7 - 2(radical y+6)
-6 = - 2(radical y+6)
3 = radical y+6 so
9 = y+6
y = 3
2006-11-06 11:07:49 · answer #1 · answered by Anonymous · 0⤊ 0⤋
y=3
y+1=y+6 - 2*sqrt(y+6) + 1
2*sqrt(y+6)=6
y+6=9
y=3
whit the conditions that y> -1and y> -6 => y > -1
the solution is y=3
2006-11-06 19:06:47 · answer #2 · answered by AnSwERinho 3 · 2⤊ 0⤋
SQUARE BOTH SIDES
y+1 = y+6 - 2 sqrt(y+6) + 1
-6 = -2sqrt(y+6)
3= sqrt(y+6)
SQUARE AGAIN
9= y+6
y=3
2006-11-06 19:31:20 · answer #3 · answered by MollyMAM 6 · 0⤊ 0⤋
square both sides to get y plus one equals y plus 6 minus 2.
then its easy to sove
2006-11-06 19:08:42 · answer #4 · answered by Star Eyed 2 · 0⤊ 1⤋
IS RADICAL 10
2006-11-06 19:02:18 · answer #5 · answered by steven_jonson2003 1 · 0⤊ 1⤋
What language is that in? lol
what is the problem anyway? there is already an = sign! i hav no clue buddy
2006-11-06 19:02:21 · answer #6 · answered by dramateen23 3 · 0⤊ 0⤋
use the calcator!
2006-11-06 19:01:21 · answer #7 · answered by FP 6 · 0⤊ 1⤋