sec(-x)cos(-x)?

0 ⤊

Simplify the expression to either 1 or -1

2006-11-06 10:10:31 · 2 answers · asked by Chrystal D 1 in Science & Mathematics ➔ Mathematics

sec(-x)cos(-x); cos(-x)=cos(x); sec(-x)=sec(x)
sec(x)cos(x); sec(x)=1/cos(x)
[1/cos(x)]cos(x)
cos(x)/cos(x)=1

2006-11-06 10:18:56 · answer #1 · answered by venomfx 4 · 0⤊ 0⤋

sec(-x)cos(-x)
(-1/cos(x)) * -cos(x)
(cos(x))/(cos(x))
1

ANS : 1

2006-11-06 18:46:49 · answer #2 · answered by Sherman81 6 · 0⤊ 0⤋