My Question:
Consider a solution which is 6.3 M with respect to H3PO4. How many moles of this acid are in 216mL of this solution?
Sample Question:
Consider a solution which is 6.3 M with respect to H3PO4. How many moles of this acid are in 283mL of this solution?
ANSWER: 1.78
Can someone please help me with the first question? Thanks!
2006-11-06 09:45:45 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
molarity = moles/L
so just plug in what you have! 6.3M= mol/0.216 L just multiple 6.3 by 0.216 and you will get the moles of the acid (i dnt have a calculator on me right now, but just do the calc out and theres ur answer! ) :)
2006-11-06 09:53:38 · answer #1 · answered by Anonymous · 0⤊ 0⤋
n = C*V (where n: the quantity of the H3PO4 in moles, C the concentration - molarity - and V the volume in L). So:
n = 6.3*0.216 = 1.3608 mol or 1.36 mol approx.
2006-11-06 10:22:43 · answer #2 · answered by Dimos F 4 · 0⤊ 0⤋
6.3 M means 6.3 moles in 1 liter.
So you have 0.216 liter.
1 liter ===> 6.3 mol
0.216 liter ===> x
x = 6.3 * 0.216 mol = 1.36 mol
2006-11-06 10:27:55 · answer #3 · answered by Dr. J. 6 · 0⤊ 0⤋