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and what happens to the temperature if work is done?

2006-11-06 09:43:19 · 7 answers · asked by Anonymous in Science & Mathematics Physics

so if work is done, the temperature will....decrease?

2006-11-06 09:50:10 · update #1

7 answers

An adiabatic ("a" as in "not" + "diabatic", meaning "heat") system is one in which no heat is exchanged with its surroundings. In this case, the First Law of Thermodynamics becomes:

change in internal energy = -work done by the system

For example, if a parcel of air expands, doing positive work on its surroundings, its internal energy will drop. Since, internal energy is directly proportional to temperature in an ideal gas, this means the air will cool.

2006-11-06 09:50:37 · answer #1 · answered by stormfront105 2 · 1 0

In thermodynamics, an adiabatic process or an isocaloric process is a process in which no heat is transferred to or from working fluid. The term "adiabatic" literally means an absence of heat transfer; for example, an adiabatic boundary is a boundary that is impermeable to heat transfer and the system is said to be adiabatically (or thermally) insulated. An insulated wall approximates an adiabatic boundary. Another example is the adiabatic flame temperature, which is the temperature that would be achieved by a flame in the absence of heat loss to the surroundings. An adiabatic process which is also reversible is called an isentropic process.

The opposite extreme, in which the maximum heat transfer with its surroundings occurs, causing the temperature to remain constant, is known as an isothermal process. Since temperature is thermodynamically conjugate to entropy, the isothermal process is conjugate to the adiabatic process for reversible transformations.

A transformation of a thermodynamic system can be considered adiabatic when it is quick enough so that no significant heat transfer happens between the system and the outside. At the opposite, a transformation of a thermodynamic system can be considered isothermal if it is slow enough so that the system's temperature can be maintained by heat exchange with the outside.

2006-11-06 09:45:38 · answer #2 · answered by Brite Tiger 6 · 1 0

In quantum mechanics, an adiabatic process is an infinitely slow change in the Hamiltonian of a system. Adiabatic processes are important idealizations of "sufficiently slow" processes and bear important consequences for quantum mechanics (see adiabatic theorem).

Note that the term "adiabatic" is traditionally used in thermodynamics to describe processes without the exchange of heat between system and environment (see adiabatic process). The definition above is closer to the thermodynamical concept of a quasistatic process, and has no direct relation with heat exchange. These two different definitions can be the source of much confusion, especially when the two concepts (heat exchange and sufficiently slow processes) are present in a given problem.

2006-11-06 09:54:30 · answer #3 · answered by Anonymous · 1 0

ad·i·a·bat·ic (d--btk, d--) KEY

ADJECTIVE:

Of, relating to, or being a reversible thermodynamic process that occurs without gain or loss of heat and without a change in entropy.

If work is done within an adiabatic system, the temperature must decrease, since the energy is conserved.

2006-11-06 09:49:48 · answer #4 · answered by Helmut 7 · 1 0

When work is done by the system the temperature goes down and when work is done on to the system the temperature goes up.

2006-11-06 09:45:41 · answer #5 · answered by feanor 7 · 1 0

An adiabatic system is one whose condition is changed without gaining heat from or losing heat to the surroundings.

2006-11-06 16:19:14 · answer #6 · answered by Dr. J. 6 · 0 0

by using fact the equipment is right adiabatic, greater useful manage the subject with the eq. PV^y = consistent. From right here we are able to remark that with increasing quantity, rigidity decreases. additionally from television^(y-a million) = consistent, we are able to declare as quantity will improve, Temperature decreases (by using fact y is often greater suitable than a million), it somewhat is your first end. Now, as V is increasing yet P is reducing, we won't say from this lots advice that their product is consistent, i.e. Temperature isn't consistent it somewhat is sparkling from proper adiabatic eq.

2016-12-28 14:41:11 · answer #7 · answered by jamila 3 · 0 0

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