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10 answers

Distribute the 2 to the two terms in the parentheses. Group like terms. Solve for X.

2006-11-06 06:47:19 · answer #1 · answered by Anonymous · 1 1

ok the problem is 3x+2(5x-3)=7
-3x -3xwell first get rid of the 3x you do it by subtracting it

then 2(5x-3)=7-3x then multiply 2 to the perentesease
10x-6=7-3x then add the 3x to 10x
+3x +3x
13x-6=7
add 6 to 7
13x=13
then devide
13/13=x
x=1

2006-11-06 08:54:13 · answer #2 · answered by Anonymous · 2 0

Distribute the 2.... 2 times 5x is 10x. 2 times -3 is -6. This gets you:

3x+10x-6=7

You can figure it out from here!

2006-11-06 06:43:50 · answer #3 · answered by Anonymous · 0 1

3x+2(5x-3)=7
3x +10x-6=7, add similar numbers, subtract 6 then add it to 7
13x=13, divide both sides by 13
x=1

2006-11-06 10:37:58 · answer #4 · answered by kwasson1302 1 · 0 0

Begin with the part in parentheses. Multiply the 2 by the other numbers. Add the x's together. Then isolate x by dividing and adding the other numbers from both sides of the equation.

2006-11-06 06:42:30 · answer #5 · answered by KC 7 · 2 0

Distribute the 2 so you get
3x + 10x - 6 = 7
that gets you
13x - 6 = 7

Add 6 to both sides of the equal sign...

13x = 13

x = 1

2006-11-06 06:42:04 · answer #6 · answered by chaloobe 2 · 3 2

3x + 2 (5x - 3) = 7. Distribute them first and used inverse operation.

2006-11-06 06:42:13 · answer #7 · answered by Anonymous · 0 3

3x+2(5x-3)=7
3x+10x-6=7
13-6=7

2006-11-06 06:45:01 · answer #8 · answered by Starbright 3 · 1 3

First, remember your precidence table.
Perform math withing parenteses first. Then go from there.

2006-11-06 07:28:04 · answer #9 · answered by Hut T 2 · 0 1

Please excuse my dear aunt sally.

Parenthesis
Exponents
Multiplication
Division
Addition
Lastly, Subtraction (in that order)

2006-11-06 06:42:12 · answer #10 · answered by Christabelle 6 · 3 0

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