2006-11-06 06:17:43 · 6 answers · asked by alvistodd 1 in Science & Mathematics ➔ Mathematics
There are lots:
...
1551
1661
1771
1881
1991
2002
2112
2222
2332
...
etc.
2006-11-06 06:19:43 · answer #1 · answered by Puzzling 7 · 1⤊ 0⤋
I can think of many just for this century That is assuming you use 2 digits for the month. If you do not you can do all the below for
eg
10/11/01*
20/11/02*
30/11/03*
01/11/10*
11/11/11
21/11/12
02/11/20*
12/11/21
22/11/22
03/11/30*
13/11/31
23/11/32
04/11/40*
14/11/41
24/11/42
05/11/50*
15/11/51
25/11/52
06/11/60*
16/11/61
26/22/62
07/11/70*
17/11/71
27/11/72
08/11/80*
18/11/81
28/11/82
09/11/90*
19/11/91
29/11/92
That is assuming you use 2 digits for the month. If you do not you can do all the above days and years for:
--/1/-- plus 31/1/13 and 13/1/31
--/2/--
--/3/-- plus 31/3/13 and 13/3/31
--/4/--
--/5/-- plus 31/5/13 and 13/5/31
--/6/--
--/7/-- plus 31/7/13 and 13/7/31
--/8/-- plus 31/8/13 and 13/8/31
--/9/--
* and these are out if all numbers are not expressed as 2 digits.
However if 0's are not allowed to precede units the following dates can be added:
M/N/M where M = 1,2,3,4,5,6,7,8,9 or 11and N = 1,2,3,4,5,6,7,8 or 9
AB/N/BA where A is 1,2 and 3, and B is 1,2 for N = 2,4,6,9,11 and B is also 3 for N = 1,2,5,7 or 8
I think that exhausts it.
2006-11-06 14:52:19 · answer #2 · answered by Wal C 6 · 0⤊ 0⤋
20 February 2002.
20/02/2002
2006-11-06 14:34:53 · answer #3 · answered by Anonymous · 0⤊ 0⤋
there are many years
for example:
2002
1001
3003
1111
2222
999
2006-11-06 14:50:46 · answer #4 · answered by reem h 2 · 0⤊ 0⤋
it depends on what you mean you need to be more specific
2006-11-06 14:41:22 · answer #5 · answered by Kristen V 2 · 0⤊ 0⤋
1991,1771,1881,2002,
2006-11-06 14:29:52 · answer #6 · answered by missy 2 · 0⤊ 0⤋