An object weighing 325 N in air is immersed in water after being tied to a string connected to a balance. The scale now reads 265 N. Immersed in oil, the object weighs 295 N.
(a) Find the density of the object.
(b) Find the density of the oil
2006-11-06 06:16:23 · 1 answers · asked by mastersource2005 5 in Science & Mathematics ➔ Physics
325N/9.8m/s^2=33.16 Kg=33163g
265N/9.8m/s^2=27.041Kg=27041g
33163g-27041g=6122 g of water displaced. Since water's density is 1 g/cc it is 6122 ccs displaced by the object, that is it's volume. 33163g/6122cc=4.417 g/cc, that is your density.
In oil the object weighs 295 N
295n/9.8m/s^2=30.102Kg=30102g
33163g-30102g=3061 g of oil displaced. The volume of the object stays the same (unless you add some additional information on pourous material) so if 3061 g are displaced by 6122cc, the oils density is 3061g/6122cc=0.5 g/cc
2006-11-06 06:38:35 · answer #1 · answered by SteveA8 6 · 0⤊ 0⤋