English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

3 answers

let x=0.7333333333...........
10x=7.333333333333...............................
100x=73.333333333333
subtracting2 from 3
90x=66
x=66/90
=11/15

2006-11-06 01:26:10 · answer #1 · answered by raj 7 · 3 0

Depends on where the decimal starts repeating and how many digits repeat. Let's start with non-repeating fractions...

If you had 0.7, you would put it over 10, 100, 1000, etc. depending on how many digits you had. In this case you have one digit so it would be: 7/10.

Now if you have repeating decimals starting right at the beginnning (e.g. 0.3333), you put them over the corresponding number of 9s. So 0.3 has one repeating digit, so it is 3/9 = 1/3.
If you had 0.4141414, you would make this 41/99. Or if you had 0.135135135 --> 135/999 = 5/37

Now if you have both, say 0.73333, you would put the first part over the power of ten matching the number of digits (e.g. 7/10) and the second part over the corresponding number of 9s... normally that would be 3/9, but it is offset, so it would be 3/90. You add the number of zeroes equal to the offset.
Your final answer is 7/10 + 3/90. Then you can simplify as:
63/90 + 3/90 = 66/90 = 22/30 = 11/15.

Let's take another example:
0.352727272.

This would be 35/100 + 27/9900.

Or if you had:
0.1234567676767 would be 12345/100000 + 67/9900000

Got it?

2006-11-06 02:34:40 · answer #2 · answered by Puzzling 7 · 0 0

simple, depending on where you end the 3's, you put it over 100, 1000, 10000 etc. easy as pie.

73/100
733/1000
7333/10000 etc

2006-11-06 01:37:02 · answer #3 · answered by trish the dish 3 · 0 1

fedest.com, questions and answers