A bat flying in a cave emits a sound and receives its echo 0.4 s later. How far away is the cave wall?

Question

( distance-wise in meters)

Answer 1

The distance of the cave wall is 66.28 meters in normal calculations distance =speed *time
in this case distance =speed *1/2(time)
But!

speed of sound is usually in( 331.4meters/second+0.6Tc )all in meters per second.

the speed of sound is usually varriant according to the medium also room temperature. in that the higher the temperature the faster the speed of sound.

lets say the room temperature of the cave is 22 degrees celsius 77f.

the speed of sound will be......
normal speed of sound+(temperature *0.6Tc)

so in a cave of 25degrees

the speed of sound will be 331.4+(0.6*25) =346.65

So the resault distance is 346.65*time of which is 0.2seconds to give about 69.33 meters

Answer 2

0.2 seconds away from where the bat is:
it takes 0.2 sec. fro the sound to reach the wall and 0.2 sec. for the echo to reach the bat.
and if you know the speed of sound you can acctually calculate the distance:
d=ts
if t = 0.2 and s is the sprrd of the sound per second, then:
d= 0.2s

Answer 3

v=velocity of sound= 330m/s
d=distance (remember that sound will travel 2 times the distance, towards, and away)
t=time

use d=vt/2
d=330*0.4/2
d=66 meters!!!
n_n