A ball is thrown horizontally with an initial velocity of 20.0 meters per socond from the top of a tower 60.0?

Question

meters high. what is the initail vertical velocity of the ball. what is the approximate total time required for the ball to reach the groud. And what is the horizontal velocity of the ball just before it reaches the ground

Answer 1

Initial vert velocity is zero

for free fall

d=Vixt + 0.5xgxt^2, d=60, Vi=0, g=9.81
t=(60/(0.5x9.81))^0.5
t=3.497487084 s


If there is no air resistance, horizontal velocity doesn't change

Answer 2

Any object thrown horizontally has initial velocity equal to zero. The horizontal velocity of an object remains constant throughout its flight. Therefore, the horizontal velocity of the ball just before it reaches the ground is 20.0m/s.

To compute the time required for the ball to reach the ground, use the formula:

s=ut +1/2at^

where s is the height of the tower, u the initial vertical velocity equal to 0, a is the acceleration of gravity equal to 9.8m/s^2, and t is our unknown time in seconds. Substitute known values:

60=0*t+1/2*9.8t^2
60=4.9t^2
t^2=12.2
t=3.5s

Answer 3

The initial vertical velocity is 0 m/s.... the approx time required for the ball to reach the ground is 3.5 seconds. This is got from the equation s = u*t + (1/2)*g*t*t. Here s = 60m, u (initial velocity in the vertical direction) is 0 m/s, g (acceleration due to gravity) is 9.81 m/s^2. So t works out to 3.5 seconds approx.......the horizontal velocity of the ball remains the same when it reaches the ground, i.e 20 m/s. This is because no horizontal force acts on it....The first answer up there by logic1812 is wrong

Answer 4

Well the time I cannot figure out without looking up a formula, and as a rule I use my own knowledge, not a look up item. Your question has three parts - initial vertical velocity - 0 mph, as you describe it thrown horizontally. After falling 60 meters, its horizontal velocity will have been spent and there fore will be zero just before it reaches the ground. Time of travel, I dont know. So I wont pretend I do.

Answer 5

logic 'dropped the ball'. The horizontal velocity remains constant throughout the fall.

Vvi = 0 (horizontal throw)

t^2 = 2h/a = 2*60/9.8-----> t = 3.50 sec