When it's weighed on a balance, is the mass of the dish bigger or smaller than it's suppose to be?
2006-11-05 13:57:43 · 8 answers · asked by aSnxbByx113 2 in Science & Mathematics ➔ Chemistry
it's the same. Mass of an object has nothing to do with its temperature. The definition of mass is the amount of matter in an object. What you are measuring with a balance is the weight of an object, which is also independent of temperature, and is the force of the gravity acting on the object.
Look up the definitions of mass and weight on wikipedia.
2006-11-05 14:04:22 · answer #1 · answered by smarties 6 · 0⤊ 0⤋
The mass stays the same.
But, if weighed on a very, very sensitive balance (and in air, not in vacuum), the mass would *appear* to decrease a little. This is because the dish has expanded and displaces more air so the upward buoyancy force on it is greater (Archimedes law).
2006-11-05 22:36:07 · answer #2 · answered by Anonymous · 0⤊ 0⤋
i guess you want an answer regarding the equation e=mc2
if so here it is...
the mass would increase but just a little bit and you probably would not notice it, for the energy that is being put in the dish turns to mass. a very small mass that is unobservable to the human eye...
2006-11-05 23:21:24 · answer #3 · answered by Anonymous · 0⤊ 0⤋
Mass does not change. The density of the dish may change if it expands upon heating.
2006-11-05 22:36:56 · answer #4 · answered by Dr. J. 6 · 0⤊ 0⤋
Mass is constant. The amount of matter in an object wont be affected by temperature or anything else for that matter.
2006-11-05 22:06:08 · answer #5 · answered by pittoresque 2 · 0⤊ 0⤋
It does not matter it depends on how the matter is made if it is a big dish or small dish and what it is like ceramic or such
2006-11-05 22:20:48 · answer #6 · answered by sunshine 1 · 0⤊ 0⤋
that question cant be answered without knowing the material the dish is made of...
2006-11-05 22:19:41 · answer #7 · answered by eskew_obfuscation 3 · 0⤊ 0⤋
remains same
2006-11-05 22:05:19 · answer #8 · answered by Sudhir P 1 · 0⤊ 0⤋