2006-11-05 13:43:43 · 4 answers · asked by miko 1 in Science & Mathematics ➔ Mathematics
Given ax² + bx + c = 0, the quadratic formula tells us that:
x = [ -b ± √(b²-4ac) ] ÷ 2a
In your problem, a=3, b=12, c=1 -- simply plug these values into the quadratic formula to solve for x.
2006-11-05 13:44:29 · answer #1 · answered by dualspace 3 · 0⤊ 0⤋
x=12
2006-11-05 21:54:32 · answer #2 · answered by fritters1018 1 · 0⤊ 0⤋
3x^2 + 12x + 1 = 0
x = (-b ± sqrt(b^2 - 4ac))/(2a)
x = (-12 ± sqrt(12^2 - 4(3)(1)))/(2(3))
x = (-12 ± sqrt(144 - 12))/6
x = (-12 ± sqrt(132))/6
x = (-12 ± sqrt(4 * 33))/6
x = (-12 ± 2sqrt(33))/6
x = (1/3)(-6 ± sqrt(33))
ANS :
x = (1/3)(-6 + sqrt(33)) or (1/3)(-6 - sqrt(33))
2006-11-05 23:29:47 · answer #3 · answered by Sherman81 6 · 0⤊ 0⤋
I was wrong. First answer is correct.
2006-11-05 21:48:41 · answer #4 · answered by Honey 3 · 0⤊ 0⤋