A particle whose mass is 1 kg moves in the xy-plane with a constant speed of 5m/s in the positive x-direction.

Question

It also moves along y= 7m. Find the magnitude of its angular momentum relative to the point (Xo, Yo), where Xo= 2m and Yo= 12m, answer in kg m^2/s.

Answer 1

The angular momentum of a particle of mass m with respect to a chosen origin is given by vector product L = r x p= mvr sin θ In your problem r sin θ is equal to the difference in the y coordinates 12-7=5. Draw a picture to help understand this.