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say you have four numbers arranged in the corner of a square, you add them once per second for ten seconds, what is the sum, if the numbers are 3, 2, 5, and 1

2006-11-05 13:04:50 · 4 answers · asked by Book of Changes 3 in Science & Mathematics Mathematics

4 answers

110

2006-11-05 13:13:13 · answer #1 · answered by Other sheep 4 · 0 0

3+2+5+1=11 add them 10 times =11*10=110

2006-11-05 21:30:40 · answer #2 · answered by yupchagee 7 · 0 0

So you add them ten times. Each of them? You're not being 100% clear. And what does the square have to do with any of this?

2006-11-05 21:08:32 · answer #3 · answered by Anonymous · 0 0

You are a smart guy, to create a same numbers with your riddle.

2006-11-05 21:11:30 · answer #4 · answered by he he he 2 · 0 0

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