Slowing Down a Train?

Question

A train has a mass of 4.56E+6 kg and is moving at 82.7 km/hr. The engineer applies the brakes, which results in a net backward force of 1.63E+6 N on the train. The brakes are held on for 28.7 s. The Speed of the Train is: 1.27×101 m/s

How far does it travel during this period?

The answer for part one was wrote wrong, instead of 1.27×101 m/s it is suppose to be 1.27x10^1

Answer 1

i

Answer 2

F = m*a and s = (1/2)*a*t^2 should give it to you.