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I don't understand the graphing aspect of it??

2006-11-05 12:22:44 · 3 answers · asked by lil_one479 1 in Science & Mathematics Mathematics

3 answers

for a graph, go to http://www.calculator.com/calcs/GCalc.html

type in

e^x
click enter
e^(2x)
click enter

and then seperately

log(x)
click enter
log(2x)
click enter

by the way

e^(2x) = (e^x)^2

so in comparison to e^x, the problem was squared

as for

log(2x) = log(2) + log(x)

so in comparison to log(x)

log(2x) was moved to the the left log(2) units

2006-11-05 12:51:02 · answer #1 · answered by Sherman81 6 · 0 0

enable's get the logs to the comparable factor on the 1st difficulty: log(x^3)+log(x) = 8 mutually as 2 logs are being extra, we are able to combine them by multiplying the words of the log: log(x^3*x) = 8 log(x^4) = 8 now convert to exponent variety understanding the undeniable fact that the backside of the log(as a effect it particularly is 10) is raised to the respond and equals the time era of the log. 10^8 = x^4 x^4 = 10^8 x = + or - 10^2 = + or - one hundred. precise, we will not have -one hundred for this reason of fact we will not take the log of unfavorable numbers. So the respond is one hundred. b)4^(x+a million) = 4^x+6 subtract the 4^x to the a number of factor 4^(x+a million) - 4^x = 6 wreck 4^(x+a million) into 4^x*4 4(4^x) - 4^x = 6 if we've 4 4^x's and are taking one away, we then have 3 3(4^x) = 6 divide by 3 4^x = a million/2 or 2^-a million make 4 into 2's 2^(2x) = 2^(-a million) 2x = -a million x = -a million/2 voila

2016-10-21 08:07:19 · answer #2 · answered by titman 4 · 0 0

Set up a table.
Choose some x's (1, 2, 4, 8, 16, 32, etc.)
y=e^x and y=ln x
plug your x's into the equations to give you two tables of values.
graph the points (x and y coordinate system)

2006-11-05 12:27:21 · answer #3 · answered by Your Best Fiend 6 · 0 0

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