I'm studying for a general physics quiz and am having a hard time figuring out how to derive the equations to use for this problem. Don't need it solved, just need some guidance on where to start. Thanks in advance.
A skier slides horizontally along the snow for a distance of 29 m before coming to rest. The coefficient of kinetic friction between the skier and the snow is µk = 0.030. Initially, how fast was the skier going?
2006-11-05 12:15:38 · 1 answers · asked by larkinfan11 3 in Science & Mathematics ➔ Physics
The skier decelerated because of the force of friction.
Ff = µk*m*g
Also by Newton's 2nd, Ff = m*a or
a = Ff/m = µk*g
And one of the motion equations:
V^2 = Vo^2 + 2*a*s should get the rest of the answer for you (Vo and 'a' have opposite directions, so set 'a' as negative).
2006-11-05 13:05:00 · answer #1 · answered by sojsail 7 · 0⤊ 0⤋