2006-11-05 11:36:45 · 5 answers · asked by william r 1 in Science & Mathematics ➔ Mathematics
I'm not sure what answer you are referring to. If you're talking about the fact that tan x and csc x are both negative in the quadrant containing (3, -2), then that is not false - they really are both negative in that quadrant.
2006-11-05 11:44:04 · answer #1 · answered by Pascal 7 · 0⤊ 0⤋
This answer is true. (3,-2) is in the fourth quadrant. If you remember the little mneumonic device that goes:
All
Students
Take
Calculus,
you know that in the 4th quadrant, the only positive trig function value is the cosine (or the secant). The tan and the csc are both negative.
2006-11-05 11:42:44 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Do you know which quadrants tan and csc are negative in?
Recall that tan = sin/cos, and csc = 1/sin
(3,-2) is in the 4th quadrant, and in the 4th quadrant cos is positive and sin is negative
Therefore in the 4th quadrant, tan is negative (neg/pos = neg), and csc is also negative (1/neg = neg).
Therefore it is TRUE that (3,-2) is in a quadrant where both tanx and cscx are negative.
2006-11-05 11:41:39 · answer #3 · answered by dualspace 3 · 0⤊ 0⤋
tanA = y/x
cscA = r/y
r = sqrt(3^2 + (-2)^2)
r = sqrt(9 + 4)
r = sqrt(13)
tan(x) = (-2/3)
csc(x) = (-sqrt(13))/2
ANS : True, both of them land in Quadrant IV
2006-11-05 12:19:48 · answer #4 · answered by Sherman81 6 · 0⤊ 0⤋
help or please help?
2006-11-05 11:40:17 · answer #5 · answered by Anonymous · 0⤊ 0⤋