Simplify: [(x2 - x - 6) / (y2 + 3y - 10)] · [(y2 - 7y + 10) / (3x2 + x - 10)] ÷ [(x2 - 2x - 3) / (9x2 - 25)]
2006-11-05 11:31:44 · 5 answers · asked by pinaysunrise 4 in Science & Mathematics ➔ Mathematics
I would factor each quadratic and then see if I could somehow cancel some stuff out.
x² - x - 6 = (x-3)(x+2)
y² + 3y - 10 = (y+5)(y-2)
y² - 7y + 10 = (y+5)(y+2)
3x² + x - 10 = (3x-5)(x+2)
x² - 2x - 3 = (x-3)(x+1)
9x² - 25 = (3x+5)(3x-5)
Rewrite your problem with these factors and you will see that you can cancel out a lot of these terms!
2006-11-05 11:36:38 · answer #1 · answered by dualspace 3 · 1⤊ 0⤋
you do no longer, water unlike all different liquid interior the international starts off to freeze from the backside upwards, then at approximately 4 stages C undergoes an entire transformation and freezes from the precise downwards, increasing right this moment because it does so, then contracts. so at 0C its already ice, exams at the instant are not sat on a financial corporation trip monday interior the united kingdom, and this question replaced into posed in uk solutions upload a million.5 kg isn't 334 x 2 = 501, 334 x 2 is 668 consistently has been and consistently would be.!!!!!!!!!!!!!!!!!! if the temperature starts off at 0 the water will already be ice, study maths, physics, and thermodynamics, and forget approximately solutions from people who can't upload divide or multiply basic equations, and don't waste the time of people who've accomplished academic status.
2016-11-27 21:00:02 · answer #2 · answered by ? 4 · 0⤊ 0⤋
WOW! First invert the last fractionl then
factor all numerators, put them over all factored denominators, and divide out any common factors. here goes:
I will type the nums first, skip a line then type the denoms.
(x-3)(x+2)(y-5)(y-2)(3x+5)(3x-5) last is (3x-5 )
_________________________ =
(y+5)(y-2)(3x-5)(x+2)(x-3)(x+1) last is (x+1) Why they don't show
in the preview is beyond me.
(y-5)(3x+5)
_________
(y+5)(x+1)
2006-11-05 11:45:53 · answer #3 · answered by mom 7 · 1⤊ 0⤋
First, we factor and regroup:
(x-3)(x+2) * (y-5)(y-2) * (3x-5)(3x+5) / ((y+5)(y-2) * (x+2)(3x-5) * (x-3)(x+1))
Now, we cancel redundant factors:
(y-5)(3x+5) / ((y+5)(x+1))
And now we are done.
2006-11-05 11:41:34 · answer #4 · answered by Pascal 7 · 1⤊ 0⤋

First, FACTOR each polynomial…. And change  to multiply by reciprocal.

now cancel the factor  top and bottom
also cancel  top & bottom


this is what is left:

the math objects would not paste into this window.........
2006-11-05 11:59:40 · answer #5 · answered by ssssh 5 · 1⤊ 0⤋