Algebra Factoring Ax^2+Bx+C?

Question

We have to do an Algebra review for Geometry, and I forgot how to factor this:

2x^2-25x-13

Answer 1

Easy since x square has a coefficient bigger than 1, then we multiply this number by -13. The result is -26. No what two numbers multiplied gives -26, and added gives -25? The two numbres are -26 and 1. Now we factor by grouping

2xx - 26x +x -13
2x(x-13) 1(x-13)
(2x+1) (x-13)

Answer 2

What are the factors for A? 2 and 1
What are the factors of C? 13 and -1 or -13 and 1

Now write down the factors of A as (2x )(x )
You have two choices for factoring C. Put them in...

#1 (2x 13)(x 1)
#2 (2x 1)(x 13)

What is missing are the signs. Look at the B coefficent. It is larger than any C factor (13 or 1) and it is negative. So, #2 must be the form because when multipled, you get 26x from the outside and x from the inside. Now, choose the correct signs inside the paratheses.

Answer 3

first, notice that the first term has the numerical coefficient of two

which has the factors of 2 and 1.

next, we see that the last term has the numerical coefficient of

thirteen which has the factors of 13 and 1.

after that, it goes like this

( 2x 13 ) * ( x 1 ) or ( 2x 1 ) * ( x 13 )

we also see that the middle term is -25 so think of them which

of the two will match to -25 when you add the product of

the first term of the first factor to the second term of the second

factor and the product of the second term of the first factor and

the first term of the second factor using positive or negative sign.

if you are right this is the answer ( 2x + 1 ) ( x - 13 ).

it is a hundred percent sure.

Answer 4

anytime i have trouble factoring, i use this formula

x = (-b ± sqrt(b^2 - 4ac))/(2a)

2x^2 - 25x - 13

x = (-(-25) ± sqrt((-25)^2 - 4(2)(-13)))/(2(2))
x = (25 ± sqrt(625 + 104))/4
x = (25 ± sqrt(729))/4
x = (25 ± 27)/4
x = (-2/4) or (52/4)
x = (-1/2) or 13

ANS : (2x + 1)(x - 13)

Answer 5

(2x+1)(x-13)