solve for x: x^2-7x= -12
2006-11-05 11:15:27 · 6 answers · asked by Eric 2 in Science & Mathematics ➔ Mathematics
x^2-7x=-12
x^2-7x+12=0
(x-4)(x-3)=0
x-4=0, x-3=0
x=4, x=3
2006-11-05 11:30:30 · answer #1 · answered by djd2009 1 · 0⤊ 0⤋
x^2 - 7x + 12 = 0 (bring the 12 to the left side)
(x -4)(x-3) ( find 2 values that add to -7 and multiply into 12)
x = +4, and +3 (solve for x)
2006-11-05 19:19:35 · answer #2 · answered by Ero T 1 · 1⤊ 0⤋
Oh, this is simple:
Add 12 to both sides of the equation:
x^2-7x+12=0
Now factor:
(X-3)(x-4)=0
X=3 or x=4
2006-11-05 19:20:36 · answer #3 · answered by anon 5 · 1⤊ 0⤋
x^2 - 7x +12 factorizes as (x-4) * (x-3) so all you need to solve is:
(x-4) * (x-3) = 0
x=3 or x=4
2006-11-05 19:19:49 · answer #4 · answered by De Bob 2 · 0⤊ 0⤋
carefully expect an AREA 51 visit
2006-11-05 19:34:22 · answer #5 · answered by Anonymous · 0⤊ 0⤋
Use the calculator dude!
2006-11-05 19:24:01 · answer #6 · answered by FP 6 · 0⤊ 1⤋