sq.root -8 x sq. root -10?

Question

Did I do this problem right?
.................................................__
I got 4 sq.root 5 (4 \|5 )

Answer 1

are you working out:

sqrt(-8) x sqrt(-10) ?

if so, this is a complex number.

sqrt(-8) x sqrt(-10)
= i x sqrt(8) x i x sqrt(10)
= i^2 x sqrt(80)

and we know that i^2 = -1, so:

= -1 x 8.94
= -8.94

Answer 2

circulate the sqrt(2x+50) to the different area by skill of subtracting it 2 sqrt (x+6) = 5 - sqrt(2x+50) sq. the two components (the main remarkable area is FOIL) 4 (x+6) = (5 - sqrt(2x+50))(5 - sqrt(2x+50)) 4x + 24 = 25 - 10 sqrt (2x+50) + 2x + 50 circulate the ten sqrt (2x+50) to the left and the 4x + 24 to the main remarkable by skill of including the alternative 10 sqrt (2x+50) = -2x + fifty one sq. the two components lower back one hundred (2x+50) = (-2x + fifty one)(-2x + fifty one) do this out, make it equivalent to 0, and resolve by skill of quadratic formulation or if available FOIL you need to do it this way because of the fact which you could no longer sq. the two components if issues are extra. this is you could no longer basically sq. each element interior the unique difficulty and get 2x+50 + 4(x+6) = 25

Answer 3

-8 X -10 =80 and 80^.5 = 8.94427191

Answer 4

It's the same as the sqrt of 80 so yes, you are correct

Answer 5

sqrt(-8)sqrt(-10)=sqrt(80)=sqrt(16*5)=
4*sqrt(5) Yup! You got it!

Answer 6

Well, sqrt(a) times sqrt(b) is sqrt(ab), so that's sqrt(80). Working backwards from the same principle, it's sqrt(16)*sqrt(5), or 4sqrt(5), so yeah.

Answer 7

sqrt(-8) * sqrt(-10)
sqrt(-4 * 2) * sqrt(-1 * 10)
2isqrt(2) * isqrt(10)

(2i^2)sqrt(20)
(2 * (sqrt(-1))^2) * sqrt(4 * 5)
(2 * -1) * 2sqrt(5)
-2 * 2sqrt(5)
-4sqrt(5)

ANS : -4sqrt(5)