ok it says:
there is a feild with a perimiter of 120m by 150m. You need to put a fence around it. If the poles are placed 2m apart how many poles will you need to put around the entire feild?
yes i know im stupid, but please i just need help :'(
2006-11-05 09:42:55 · 8 answers · asked by bulletprooflonliness 4 in Science & Mathematics ➔ Mathematics
Word problems like this can be hard. Everybody has problems with them sometimes.
It does help to draw it out. So you draw a little rectangle like this:
______________
| |
| |
|______________|
2 of the sides are 120 m and the other 2 are 150 m. So you take 2 times each of these numbers and add them together:
2(120) + 2(150)
That's your perimeter, in meters. Now if your poles are 2 m apart, you don't need one for every meter you get in your answer, you only need 1 every 2 meters. So you divide your answer by 2, and that gets your number of poles you need to put around the field.
2006-11-05 09:56:15 · answer #1 · answered by T'Vral 3 · 0⤊ 0⤋
Let's start with a smaller field. One that's 8m by 4m.
Start counting with the upper left pole and count across
1, 2, 3, 4, 5. That shouold get you to the upper right corner. Now count down 6, 7. and you're at the lower right hand corner. Count back to the left 8, 9, 10, 11 and you're at the lower left. Now count up 12 and you're done. (You don't count the post in the upper left corner twice âº) The *total* perimeter is 8+4+8+4 = 24m and you used 12 poles. Now try a couple of larger fields to convince yourself that the total number of poles needed is the total perimeter divided by 2. Just make each 'side' an even number âº
And NO! you aren't stupid. Not being naturally good at math does *not* mean that you're stupid or a bad person. It just means that you haven't, as yet, developed what mathematicians call 'insight' or 'instinct'. But if you work lots of problems, you will. You just have to think about it a bit. Ask yourself, "Is this problem 'kinda like' any other problem I've worked or seen someone else work?" Hang in there. You'll do just fine âº
Doug
2006-11-05 18:11:27 · answer #2 · answered by doug_donaghue 7 · 1⤊ 0⤋
You are not stupid. You need to step far enough back to think. First, there must be a pole at each corner of the field. So, on each 150-meter side, there must be 76 poles (one for the "zero" position and 75 more to put a pole at the 150th meter. On each 120-meter side, you already have poles at the "zero" and the "end, 120th meter," so how many do you need between? Remember that there are two 120-meter sides LOL.
2006-11-05 18:01:35 · answer #3 · answered by steve_geo1 7 · 0⤊ 0⤋
Find the perimeter (P = 2L + 2W) then divide by 2 to get the number of poles needed
2006-11-05 17:48:25 · answer #4 · answered by Joan Dark 2 · 0⤊ 0⤋
Divide the total perimeter of the fence by 2m.
2006-11-05 17:47:01 · answer #5 · answered by disgracedfish 3 · 0⤊ 0⤋
find the perimeter, (120*2+150*2) then divide that by 2
2006-11-05 17:48:14 · answer #6 · answered by hypernova4218 1 · 0⤊ 0⤋
draw it out. i think that will help u understand it
2006-11-05 17:47:33 · answer #7 · answered by heyheyhey 3 · 0⤊ 0⤋
Perimeter or 540 in this case
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2
270 Poles.
2006-11-05 17:52:47 · answer #8 · answered by Robert P 1 · 0⤊ 0⤋