What is the volume of a container that holds 25.0 grams of carbon dioxide gas at stp?

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What is the volume of a container that holds 25.0 grams of carbon dioxide gas at stp?

2006-11-05 09:02:22 · 4 answers · asked by pimp_ag_2000 1 in Science & Mathematics ➔ Chemistry

4 answers

V = nRT/P
V = (25g/44g/mol)(0.08206Latm/molK)(298K)/1atm
V = 138.9 L

2006-11-05 09:09:17 · answer #1 · answered by titanium007 4 · 1⤊ 0⤋

First find the moles of CO2. Molar mass of CO2 equals Mr = 44.

n = m/Mr, n = 25/44 mol.

Now, 1 mol of a gas occupies Vm = 22.4 L in stp (Vm: molar volume), so:

V = n*Vm, V = (25/44)*22,4, V = 12.73 L (approx)

2006-11-05 17:20:39 · answer #2 · answered by Dimos F 4 · 0⤊ 0⤋

Change grams CO2 to moles then ideal gas law PV=nRT

2006-11-05 17:13:08 · answer #3 · answered by physandchemteach 7 · 0⤊ 0⤋

44 grms is 1 mole of CO2 and would be 22.4 litres at stp.
so 25 grm is 25/44 x 22.4 litres. 12.73 litre

2006-11-05 17:56:05 · answer #4 · answered by lykovetos 5 · 0⤊ 0⤋