chem help please?

Question

2 NH3(g) + CO2(g) CN2H4O(s) + H2O(l) How many grams of urea are produced when 100. g of ammonia is reacted with 100. g of carbon dioxide?

Answer 1

Do your own homework. Cheater never win.

Answer 2

Find the moles of NH3 and CO2. Molar mass of NH3 equals Mm = 17 and molar mass of CO2 equals 44:

for NH3: n = m/Mm, n = 100/17 = 5.88 mol of NH3

for CO2: n = m/Mm, n = 100/44 = 2.27 mol of CO2

According to the equation:

2NH3 + CO2 --> H2N-CO-NH2 + H2O

2 mol of NH3 react with 1 mol CO2
5.88 mol of NH3 react with 5.88/2 = 2.94 mol of CO2 > 2.27 mol CO2

So NH3 is in excess and CO2 is the limiting reactant, and reacts fully.

Because 1 mol of CO2 gives 1 mol of urea (H2N-CO-NH2)
the 2.27 mol of CO2 give 2.27 mol of urea.

Urea has a molar mass Mm = 60, so its mass equals:

m = n*Mm, m = 2.27*60 = 136.3 g (approx)

Answer 3

bring number of moles of NH3 and CO2 and do stoichiometric ration and see which is the limiting reactant.then when you find limiting reactant use its number of mole.the put number of moles=number of moles of urea.now you have the number of moles and bring molar mass therefore m=nxM.(but if NH3 is limiting don't forget the coefficient 2 in number of moles)