4 < 3x < 16 { intergers} How do you get x by itself?

Question

Which side do you divide 3 by?

Answer 1

(4/3)<(3/3)x<(16/3)
both sides are divided by 3, so you will not change the original
inequalities.
so, 1.333 x=2,3,4,5, for all integers.

Answer 2

Divide all sides of the triangle equation by 3 :

4 < 3x < 16 , so

4/3 < x < 16/3

When dealing with inequalities, do the same thing to all "sides" of the inequalities, just like you would with a standard equality equation. Keep in mind with inequalities, though, that if you mulitply or divide by a negative number you have to reverse all the inequality signs.

So, if you had 4 < -3x < 16, you would divide all sides by -3 to get 4/3 > x > 16/3. Make sense?

Answer 3

divide both 4 and 16 by 3

Answer 4

You divide both sides by three. So you end up with 4/3 < x < 16/3, meaning x has to fall somewhere between those two fractions to make the problem true.

Answer 5

You divide both sides by 3:
4/3
I'll let you do the rest by yourself!

Answer 6

4<3x => 4/3< x =>(integers) x >=2
3x<16=> x< 16/3 => (integers) x<=5
So 2<=x<=5 => {2,3,4,5}

Answer 7

you have to divide both by 3:

therefore x: {2,3,4,5}

Answer 8

divide both side by 3 --> 1.33 < x < 5.333

{2,3,4,5}