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what volume of O2 (m^3) is needed for the complete combustion of 114g of C3H8 at 28 degrees celcius and 100kPa?

2006-11-05 08:17:38 · 2 answers · asked by Anonymous in Science & Mathematics Chemistry

2 answers

PV=nRT
V = nRT/P
V = (114g/44g/mol)(0.08206L-atm/mol-K)(28+273K)/0.987atm
V = 64.84L or 0.0648 m^3

2006-11-05 08:53:01 · answer #1 · answered by titanium007 4 · 0 0

0.0163542 m^3

2006-11-05 16:45:17 · answer #2 · answered by Master 2 · 0 1

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