1) I have to figure out what the least 3-digit squeare number is.
2) What 2 digit-number has two one digit factors that have a sum of 16 and a difference of two?
3) 9 is the GCF of 18 and this 2-digit number between 50 and 60.
4) The only composite number between 0 and 6.
I did most of the work, but I need a little bit help because my dad refuses to help me.
2006-11-05 07:44:58 · 5 answers · asked by AJ 2 in Science & Mathematics ➔ Mathematics
It's been awhile but 100? 63? I don't remember what a composite number is so I can't even guess there.
2006-11-05 07:49:23 · answer #1 · answered by zara01 4 · 0⤊ 0⤋
1) I think the easiest way to calculate this is to calculate the square of each number until you get a three-digit square. So, 1, 4, 9, 16, 25, 36, 49, 64, 81, 100. The answer is 100.
2) If the numbers have a sum of 16 and a difference of two, then think of it this way. Whatever the smaller number is, the larger is that plus two. They add up to 16. So the smaller number, plus the smaller number, plus two, is 16. That means that 2 * the smaller number is 16-2, or 14. The smaller number is 7 and the larger is 9. Their product, 63, is the answer. (I'm sorry, that was a pretty wordy explanation, but I don't really know middle school curricula and I'm not sure whether you've had any algebra yet.)
3) If 9 is the GREATEST common factor, that implies that it must be a factor in the first place. There's only one number between 50 and 60 that's divisible by 9: 54.
4) Remember, a composite number is one that's divisible by something other than 1 and itself. To find the lowest possible composite number, multiply the lowest number other than 1 (2) by itself to get 4. (6 is also a composite number, but since the question implies that there's only one, I'm guessing that it wasn't meant to include 0 and 6.)
2006-11-05 15:54:21 · answer #2 · answered by Amy F 5 · 0⤊ 0⤋
#1 square is the number times itself to equal a square 10*10=100
#2 7+9=16 difference of 2
#3 9 is GCF of 18 and 54
#4 Since a composite # has factors other than one and itself you can eliminate 1,2 (2,1),3(3,1)and 5 (5,1). Your answer is 4 (1,2,4)
2006-11-05 15:48:36 · answer #3 · answered by mickey 3 · 0⤊ 0⤋
1. 100
2. 9 and 7
3. 54
4. 4
2006-11-05 15:48:52 · answer #4 · answered by Anonymous · 0⤊ 0⤋
1) 9x9=81; 10x10=100. answer: 100.
2) 79 or 97. 7+9=16; 9-7=2.
3) not sure
4) not sure
2006-11-05 15:59:05 · answer #5 · answered by Rex Rhino 2 · 0⤊ 0⤋