two resistors and an ammeter connected in series to a 6v DC supply. the distance of the ammeter is so small that it can be ignored.
What is the combined resistance of the 8ohm and 4 ohm resistors in series...
what is the current supplied by the 6v DC supply?
state the value of the current recorded by the ammeter
l----Q-l___8ohm___l----l
l ...............................l
+P ............................ l
6V.............................(A)
-R ..............................l
l ................................l
l--------S-l__4ohm__l---l
state the value of the current in section PQ of the curcuit
state the value of the current in section SR of the circuit
Ignore the dots in the diagram the thing would not accept my spaces
2006-11-05 07:12:26 · 2 answers · asked by ██████████ 3 in Science & Mathematics ➔ Physics
l----Q-l___8ohm___l----l
l .................................l
+P ............................ l
6V...............................l
-R ..............................l
l .................................l
l--------S-l__4ohm__l---l
Ignore the dots they are there as the thing would not accept my spaces
(a) ammeter
l___8ohm___l resistor of 8 ohms
+ and - are the batteries
2006-11-05 07:14:20 · update #1
a) combined resistance in series - add them up
That is, 8ohm + 4 ohm = 12ohm
b) V=IR so, I = V/R = 6/12 = 0.5A
c) Ammeter in series reads the same value throughout. So, 0.5A
Sorry but I can't understand your circuit diagram!! Try explainig it!
2006-11-05 07:26:09 · answer #1 · answered by alexsopos 2 · 0⤊ 0⤋
What is the combined resistance of the 8ohm and 4 ohm resistors in series...
They are in series so they add to 12 ohms.
what is the current supplied by the 6v DC supply?
I = V/R = 6/12 = 0.5 amps
state the value of the current recorded by the ammeter, in section PQ, in section SR of the circuit?
I = V/R = 6/12 = 0.5 amps - current is the same throughout a series circuit
2006-11-05 15:30:31 · answer #2 · answered by sojsail 7 · 0⤊ 0⤋